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196=53x-x^2
We move all terms to the left:
196-(53x-x^2)=0
We get rid of parentheses
x^2-53x+196=0
a = 1; b = -53; c = +196;
Δ = b2-4ac
Δ = -532-4·1·196
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-45}{2*1}=\frac{8}{2} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+45}{2*1}=\frac{98}{2} =49 $
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